3x^2=25x=8

Solution for 3x^2=25x=8 equation:

3x^2=25x=8

We move all terms to the left:

3x^2-(25x)=0

a = 3; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·3·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*3}=\frac{0}{6}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*3}=\frac{50}{6}
=8+1/3
$